Gujarati
3-2.Motion in Plane
normal

A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = {40^o})$

A

$2v\cos {40^o}$

B

$2v\sin {40^o}$

C

$2v\sin {20^o}$

D

$2v\,\cos {20^o}$

Solution

(c) Change in velocity = $2v\sin (\theta /2)$$ = 2v\sin 20^\circ $

Standard 11
Physics

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