Gujarati
Hindi
3-2.Motion in Plane
hard

A particle is projected from the ground at an angle of $\theta $ with the horizontal with an initial speed of $u$. Time after which velocity vector of the projectile is perpendicular to the initial velocity is

A

$u /g\,\, sin\,\, \theta $

B

$u /g\,\, cos\,\, \theta $

C

$2u /g\,\, sin\,\, \theta $

D

$2u \,\, tan\,\, \theta $

Solution

$\operatorname{since}_{x} v \perp u$ or $v . u=0$

or $(u+a t) u=0$

or $u . u+(a . u) t=0$

or $u^{2}+g u t \cos \left(90^{\circ}+\theta\right)=0$

(angle between $\left.u \text { and } u \text { is } 90^{\circ}+\theta\right)$

or $u-g t \sin \theta=0$ or $t=\frac{u}{g \sin \theta}$

Standard 11
Physics

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