A particle is rotating in a circle of radius | vedclass

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Question

(a)

$\omega=\frac{v}{R}=\frac{4}{1}=4\,rad / s$

$	heta=\omega t=4\,rad$

$	ext { Displacement }=A B=2 R \sin \frac{	heta}{2}$

$=2 \sin 2

Vedclass · Accepted Answer

$( A \rightarrow r , B \rightarrow q , C \rightarrow r , D \rightarrow p )$

Vedclass · Answer

(a)

$\omega=\frac{v}{R}=\frac{4}{1}=4\,rad / s$

$	heta=\omega t=4\,rad$

$	ext { Displacement }=A B=2 R \sin \frac{	heta}{2}$

$=2 \sin 2 	ext { unit }$

$	ext { Distance }=v t=4 	ext { unit }$

$	ext { Average velocity }=\frac{	ext { Displacement }}{	ext { Time }}=2 \sin 2 	ext { unit }$

$	ext { And average acceleration }=\frac{|\Delta v|}{\Delta t}$

From subtraction of vectors, we can find that change in velocity from $A$ and $B$ is $2 v \sin \frac{	heta}{2}=8 \sin 2$ unit

$	herefore \quad 	ext { Average acceleration } =\frac{8 \sin 2}{1}$

$=8 \sin 2 	ext { unit }$

Colum $I$	Colum $II$
$(A)$ Displacement	$(p)$ $8 \sin 2$
$(B)$ Distance	$(q)$ $4$
$(C)$ Average velocity	$(r)$ $2 \sin 2$
$(D)$ Average acceleration	$(s)$ $4 \sin 2$

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