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2.Motion in Straight Line
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A particle moves along $X-$axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6{t^2})\,m$. The initial velocity of the particle is.......$m/s$
A
$ - 5$
B
$6$
C
$ - 3$
D
$3$
Solution
(a) The velocity of the particle is
$\frac{{dx}}{{dt}} = \frac{d}{{dt}}(2 – 5t + 6{t^2}) = (0 – 5 + 12t)$
For initial velocity $t = 0$, hence $v = – 5\;m/s$.
Standard 11
Physics