A particle moves along a circle of radius&nbs | vedclass

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Question

$a_{t}=r \alpha=$ const. $\Rightarrow \alpha=$ const.

${\omega _i} = 0$          $	heta=2 \pi$

$\omega_{f}=\frac{V}{r}

Vedclass · Accepted Answer

$40$

Vedclass · Answer

$a_{t}=r \alpha=$ const. $\Rightarrow \alpha=$ const.

${\omega _i} = 0$          $	heta=2 \pi$

$\omega_{f}=\frac{V}{r}=\frac{80}{(20 / \pi)}=4 \pi$

$\alpha=\frac{\omega_{f}^{2}-\omega_{i}^{2}}{2 	heta}=2 \pi \operatorname{rad} / \sec ^{2}$

$\mathrm{a}_{\mathrm{t}}=\frac{20}{\pi} 	imes 2 \pi=40 \mathrm{\,m} / \mathrm{s}^{2}$

Colum $I$	Colum $II$
$(A)$ Displacement	$(p)$ $8 \sin 2$
$(B)$ Distance	$(q)$ $4$
$(C)$ Average velocity	$(r)$ $2 \sin 2$
$(D)$ Average acceleration	$(s)$ $4 \sin 2$

A particle moves along a circle of radius $\left( {\frac{{20}}{\pi }} \right)\,m$ with constant tangential acceleration. If the velocity of the particle is $80 \,m/s$ at the end of the second revolution after motion has begin, the tangential acceleration is

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