A particle moves along a parabolic path y=9 x^2 in such a way that x component of velocity remains c

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3-2.Motion in Plane

hard

A particle moves along a parabolic path $y=9 x^2$ in such a way that the $x$ component of velocity remains constant and has a value $\frac{1}{3}\,m / s$. The acceleration of the particle is $.......m / s ^2$

A

$\frac{1}{3}$

B

$3$

C

$\frac{2}{3}$

D

$2$

Solution

$y=9 x^2$

$\frac{d x}{d t}=\frac{1}{3}$

$\frac{d y}{d t}=18 x \frac{d x}{d t}=18x\times \frac{1}{3}=6x$

$v_y=\frac{d y}{d t}=6x$

$a_y=\frac{d v_y}{d t}=6\frac{d x}{d t}=6\times \frac{1}{3}=2\; m / s ^2$

Standard 11

Physics

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