A particle moves in a circle of radius $25\,cm$ at two revolutions per sec. The acceleration of the particle in $m/s^2$ is

forceA particle moves with constant speed $v$ along a circular path of radius $r$ and completes the circle in time $T$. The acceleration of the particle is

A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ )$

A man standing on the roof of a house of height $h$ throws one particle vertically downwards and another particle horizontally with the same velocity $u$. The ratio of their velocities when they reach the earth's surface will be

A particle is moving in a circular path. The acceleration and momentum vectors at an instant of time are $\vec{a}=2 \hat{i}+3 \hat{j} m / s ^2$ and $\overrightarrow{ p }=6 \hat{ i } + 4 \hat{ j } kgm /$ $s$. Then the motion of the particle is

The ratio of angular speeds of minute hand and hour hand of a watch is