A particle moves in east direction with 15 ,m/sec . for 2, sec then moves northward with 5, m/sec .

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3-2.Motion in Plane

medium

A particle moves in east direction with $15 \,m/sec$. for $2\, sec$ then moves northward with $5\, m/sec$. for $8 \,sec$. then average velocity of the particle is

A$5\, m/sec\,$ due $E -37^o -N$

B$5\, m/sec\,$ due $N -37^o -E$

C$7\, m/sec\,$ due $S -37^o -W$

D$10\, m/sec\,$ due $N -37^o -E$

Solution

$\begin{aligned} \overrightarrow{v}_{av} &=\frac{\text { total displacement }}{\text { total time }} \\ &=\frac{(15 \hat{\mathrm{i}}) \times 2+(5 \hat{\mathrm{j}}) \times 8}{2+8} \\ &=3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}} \\ &=5 \mathrm{m} / \mathrm{s} \mathrm{N}-37^{\circ}-\mathrm{E} \end{aligned}$

Standard 11

Physics

A $NCC$ parade is going at a uniform speed of $9\,km / h$ under a mango tree on which a monkey is sitting at a height of $19.6\,m$. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is $…m$
(Given $g=9.8\,m / s ^{2}$ )

medium

(JEE MAIN-2022)

The position vector of a particle is determined by the expression $\vec r = 3{t^2}\hat i + 4{t^2}\hat j + 7\hat k$ The distance traversed in first $10 \,sec$ is…….. $m$

medium

A particle is moving with velocity $\vec v = K(y\hat i + x\hat j)$ where $K$ is a constant. The general equation for its path is

hard

(AIEEE-2010)

A body starts from rest from the origin with an acceleration of $6\,m/{s^2}$ along the $x-$axis and $8\,m/{s^2}$ along the $y-$axis. Its distance from the origin after $4 \,seconds$ will be……..$m$

medium

The position of a particle is given by

$r =3.0 t \hat{ i }-2.0 t^{2} \hat{ j }+4.0 \hat{ k } \;m$

where $t$ is in seconds and the coefficients have the proper units for $r$ to be in metres.

$(a)$ Find the $v$ and a of the particle?

$(b)$ What is the magnitude and direction of velocity of the particle at $t=2.0 \;s ?$

medium

A particle moves in east direction with $15 \,m/sec$. for $2\, sec$ then moves northward with $5\, m/sec$. for $8 \,sec$. then average velocity of the particle is

Solution

Similar Questions

A $NCC$ parade is going at a uniform speed of $9\,km / h$ under a mango tree on which a monkey is sitting at a height of $19.6\,m$. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is $…m$ (Given $g=9.8\,m / s ^{2}$ )

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A $NCC$ parade is going at a uniform speed of $9\,km / h$ under a mango tree on which a monkey is sitting at a height of $19.6\,m$. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is $…m$
(Given $g=9.8\,m / s ^{2}$ )