A particle of mass 1, kg moving with velocity | vedclass

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Question

Let velocity of $1 \mathrm{kg}$ after collision is $\mathrm{v}$

$\frac{1}{2}(1)\left(\mathrm{v}^{2}\right)=\left[\frac{1}{2}(1)(1)\right] \frac{1}{

Vedclass · Accepted Answer

$\frac{1}{3} \,kg$

Vedclass · Answer

Let velocity of $1 \mathrm{kg}$ after collision is $\mathrm{v}$

$\frac{1}{2}(1)\left(\mathrm{v}^{2}\right)=\left[\frac{1}{2}(1)(1)\right] \frac{1}{4}$

$\mathrm{v}=\frac{1}{2} \mathrm{m} / \mathrm{s}$

Now, conserving momentum in collision

$(1)$ $(1)=(1)\left(\frac{1}{2}\right)+\mathrm{mv} \Rightarrow \mathrm{mv}=\frac{1}{2}$

Also

$\frac{v-\frac{1}{2}}{1}=1 \Rightarrow v=\frac{3}{2} m / s$

so $\mathrm{m}=\frac{1}{3} \mathrm{kg}$

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