A particle of mass $m$ is projected with a velocity $V$ making an angle of $45^o$ with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is
A particle of mass $m$ is projected with a velocity $V$ making an angle of $45^o$ with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is
- A
zero
- B
$\frac{{m{V^2}}}{{\sqrt 2 \,g}}$
- C
$\frac{{m{V^2}}}{{4\sqrt 2 \,g}}$
- D
$m\sqrt {2g{h^3}} $
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