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Question

The radius $r$ of the circular path is given by (see Fig.)

$\frac{\mathrm{mv}^{2}}{\mathrm{r}}=\mathrm{qvB}$

or $v=\frac{q B}{m}(r)$

$	heref

Vedclass · Accepted Answer

$q\left( {b - a} \right)\,B/\,m$

Vedclass · Answer

The radius $r$ of the circular path is given by (see Fig.)

$\frac{\mathrm{mv}^{2}}{\mathrm{r}}=\mathrm{qvB}$

or $v=\frac{q B}{m}(r)$

$	herefore \mathrm{v}_{\min }=\frac{\mathrm{qB}}{\mathrm{m}}\left(\mathrm{r}_{\min }ight)=\frac{\mathrm{qB}}{\mathrm{m}}(\mathrm{b}-\mathrm{a})$

which is choice $( 2)$

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