7.Gravitation
easy

A particle of mass $10\, g$ is kept of the surface of a uniform sphere of mass $100\, kg$ and a radius of $10\, cm .$ Find the work to be done against the gravitational force between them to take the particle far away from the sphere. (you make take $\left.G=6.67 \times 10^{-11} Nm ^{2} / kg ^{2}\right)$

A

$3.33 \times 10^{-10} \;J$

B

$13.34 \times 10^{-10} \;J$

C

$6.67 \times 10^{-9}\; J$

D

$6.67 \times 10^{-10}\; J$

(AIIMS-2019)

Solution

The work to be done against the gravitational force is,

$W=\frac{G M m}{R}$

$W=\frac{6.67 \times 10^{-11} \times 100}{0.1} \times \frac{10}{1000}$

$W=6.67 \times 10^{-10} J$

Standard 11
Physics

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