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5.Work, Energy, Power and Collision
medium
A particle of mass $200 \,g$, is whirled into a vertical circle of radius $80 \,cm$ using a massless string. The speed of the particle when the string makes an angle of $60^{\circ}$ with the vertical line is $1.5 \,ms ^{-1}$. The tension in the string at this position is ........... $N$
A
$1$
B
$1.56$
C
$2$
D
$3$
Solution
(b)
$T-m g \cos \theta=\frac{m v^2}{R}$
$\theta=60^{\circ}$
Solving this
$T=1.56 \,N$
Standard 11
Physics
Similar Questions
medium
A stone of mass $m$ tied to the end of a string revolves in a vertical circle of radius $R$. The net forces at the lowest and highest points of the circle directed vertically downwards are:
Choose the correct alternative
Lowest Point | Highest Point |
$(a)$ ${mg – {T_1}}$ | ${mg + {T_2}}$ |
$(b)$ ${{m_g} + {T_1}}$ | ${{m_g} – {T_2}}$ |
$(c)$ ${mg + {T_1} – \frac{{mv_1^2}}{R}}$ | ${mg – {T_2} + \frac{{mv_1^2}}{R}}$ |
$(d)$ ${mg – {T_1} – \frac{{mv_1^2}}{P}}$ | ${mg + {T_2} + \frac{{mv_1^2}}{p}}$ |
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