Gujarati
3-2.Motion in Plane
easy

A particle of mass $M$ moves with constant speed along a circular path of radius $ r$ under the action of a force $F$. Its speed is

A$\sqrt {\frac{{r\,F}}{m}} $
B$\sqrt {\frac{F}{r}} $
C$\sqrt {F\,m\,r} $
D$\sqrt {\frac{F}{{m\,r}}} $

Solution

(a) $F = \frac{{m{v^2}}}{r}$
$⇒$ $v = \sqrt {\frac{{rF}}{m}} $
Standard 11
Physics

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