A particle travels half of distance of a straight journey with a speed 6 ,m / s . remaining part of

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2.Motion in Straight Line

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A particle travels half of the distance of a straight journey with a speed $6 \,m / s$. The remaining part of the distance is covered with speed $2 \,m / s$ for half of the time of remaining journey and with speed $4 \,m / s$ for the other half of time. The average speed of the particle is ....... $m / s$

A

$3$

B

$4$

C

$3 / 4$

D

$5$

Solution

(b)

From $C$ to $B$ the time interval of travelling is same.

So, $v_{ av }=\frac{v_2+v_3}{2}=\frac{2+4}{2}=3 \,m / s$

Now, first half is covered with $6 \,ms ^{-1}$ and second half with $3 \,ms ^{-1}$. So when distances are same.

$v_{ av }=\frac{2 v_1 v_2}{v_1+v_2}=\frac{2 \times 6 \times 3}{6+3}=4 \,ms ^{-1}$

$v_{ av }=4 \,ms ^{-1}$

Standard 11

Physics

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