Gujarati
Hindi
7.Gravitation
medium

A planet orbits in an elliptical path of eccentricity $e$ around a massive star considered fixed at one of the foci. The point in space, where it is closest to the star is denoted by $P$ and the point, where it is farthest is denoted by $A$. Let $v_P$ and $v_A$ be the respective speeds at $P$ and $A$, then

A

$\frac{v_P}{v_A}=\frac{1+e}{1-e}$

B

$\frac{v_P}{v_A}=1$

C

$\frac{v_P}{v_A}=\frac{1+e^2}{1-e}$

D

$\frac{v_P}{v_A}=\frac{1+e^2}{1-e^2}$

(KVPY-2012)

Solution

(a)

By conservation of angular momentum,

We have,

$L_P=L_A$

$\Rightarrow \quad m v_P r_P=m v_a r_a$

So, ratio of speeds at points $P$ and $A$ is

$\frac{ V _{ P }}{ V _{ A }}=\frac{ r _{ A }}{ r _{ P }}=\frac{ a + ae }{ a – ae }$

$=\frac{a(1+e)}{a(1-e)}$

$=\frac{1+e}{1-e}$

Standard 11
Physics

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