A player throws a ball that reaches to another player in 4,s . If height of each player is 1.5,m , m

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3-2.Motion in Plane

hard

A player throws a ball that reaches to the another player in $4\,s$. If the height of each player is $1.5\,m$, the maximum height attained by the ball from the ground level is .......... $m$

A

$19.6$

B

$21.1$

C

$23.6$

D

$25.1$

Solution

$\mathrm{T}=\frac{2 \mathrm{u} \sin \theta}{\mathrm{g}}=4 \mathrm{s}$

$\therefore u \sin \theta=2 g$

$\mathrm{H}=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{g}}=\frac{4 \mathrm{g}^{2}}{2 \mathrm{g}}=2 \mathrm{g}$

$2 \times 9.8=19.6 \mathrm{m}$

Height of the ball above the ground $=19.6+1.5$

$=21.1 \mathrm{m}$

Standard 11

Physics

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