Gujarati
Hindi
2.Motion in Straight Line
easy

A point traversed $3 / 4$ th of the circle of radius $R$ in time $t$. The magnitude of the average velocity of the particle in this time interval is

A

$\frac{\pi R}{t}$

B

$\frac{3 \pi R}{2 t}$

C

$\frac{R \sqrt{2}}{t}$

D

$\frac{R}{\sqrt{2} t}$

Solution

(c)

$v_{ av }=\frac{\text { Displacement }}{\text { Time }}=\frac{\sqrt{2} R}{t}$

Standard 11
Physics

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