A point traversed $3 / 4$ th of the circle of radius $R$ in time $t$. The magnitude of the average velocity of the particle in this time interval is
A point traversed $3 / 4$ th of the circle of radius $R$ in time $t$. The magnitude of the average velocity of the particle in this time interval is
- A
$\frac{\pi R}{t}$
- B
$\frac{3 \pi R}{2 t}$
- C
$\frac{R \sqrt{2}}{t}$
- D
$\frac{R}{\sqrt{2} t}$
Similar Questions
Write relation between instantaneous and relative velocity for uniform motion.
Write relation between instantaneous and relative velocity for uniform motion.
A particle moves for $20 \,seconds$ with velocity $3 \,m/s$ and then velocity $4\, m/s$ for another $20 \,seconds$ and finally moves with velocity $5 \,m/s$ for next $20\, seconds$. What is the average velocity of the particle..........$m/s$
A particle moves for $20 \,seconds$ with velocity $3 \,m/s$ and then velocity $4\, m/s$ for another $20 \,seconds$ and finally moves with velocity $5 \,m/s$ for next $20\, seconds$. What is the average velocity of the particle..........$m/s$
A $100\, m$ long train is moving with a uniform velocity of $45\, km/hr$. The time taken by the train to cross a bridge of length $1 \,km$ is.........$s$
A $100\, m$ long train is moving with a uniform velocity of $45\, km/hr$. The time taken by the train to cross a bridge of length $1 \,km$ is.........$s$
Explain clearly, with examples, the distinction between
$(a)$ magnitude of displacement (somettmes called distance) over an interval of time, and the total length of path covered by a particle over the same interval
$(b)$ magnitude of average velocity over an interval of time, and the average speed over the same interval. [Average speed of a particle over an interval of time is defined as the total path length divided by the time interval].
Show in both $(a)$ and $(b)$ that the second quantity is either greater than or equal to the first. When is the equality sign true ? [For simplicity, consider one-dimensional motion only].
Explain clearly, with examples, the distinction between
$(a)$ magnitude of displacement (somettmes called distance) over an interval of time, and the total length of path covered by a particle over the same interval
$(b)$ magnitude of average velocity over an interval of time, and the average speed over the same interval. [Average speed of a particle over an interval of time is defined as the total path length divided by the time interval].
Show in both $(a)$ and $(b)$ that the second quantity is either greater than or equal to the first. When is the equality sign true ? [For simplicity, consider one-dimensional motion only].
A car travels half the distance with constant velocity of $40\, kmph$ and the remaining half with a constant velocity of $60 \,kmph$. The average velocity of the car in $kmph$ is
A car travels half the distance with constant velocity of $40\, kmph$ and the remaining half with a constant velocity of $60 \,kmph$. The average velocity of the car in $kmph$ is
- [AIPMT 1990]