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5.Molecular Basis of Inheritance
normal
A polypeptide is produced as dictated by $mRNA$, the number of bases on the $mRNA$ that code for the polypeptide portion containing $N$-terminal amino acid and next $13$ amino acid is
A
$26$
B
$36$
C
$42$
D
$39$
Solution
(c)One amino acid is coded by triplet base ($3$ bases) so for $13$ amino acids $13 × 3 = 39$ bases are required and $3$ bases are required for the formation of $N$ terminal amino acid from methionine. Hence total $39 + 3 = 42$ bases are required.
Standard 12
Biology
