A precipitate of AgCl is formed when equal volumes of following are mixed. [{K_{sp}} for AgCl = {10^

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6-2.Equilibrium-II (Ionic Equilibrium)

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A precipitate of $AgCl$ is formed when equal volumes of the following are mixed. $[{K_{sp}}$ for $AgCl = {10^{ - 10}}]$

A

${10^{ - 4}}\,M\,AgN{O_3}$ and ${10^{ - 7}}\,M\,HCl$

B

${10^{ - 5}}\,M\,AgN{O_3}$ and ${10^{ - 6}}\,M\,HCl$

C

${10^{ - 5}}\,M\,AgN{O_3}$ and ${10^{ - 4}}\,M\,HCl$

D

${10^{ - 6}}\,M\,AgN{O_3}$ and ${10^{ - 6}}\,M\,HCl$

Solution

(c) For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product.

Standard 11

Chemistry

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