A projectile is given an initial velocity of (hat{i}+2hat{j}),m/ s where hat{i} is along ground and

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3-2.Motion in Plane

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A projectile is given an initial velocity of $(\hat i+2\hat j)\,m/ s$ where $\hat i$ is along the ground and $\hat j$ is along the vertical. If $g = 10\,m/s^2,$ the equation of its trajectory is

$y = x -5x^2$

$y =2 x -5x^2$

$4y = 2x -5x^2$

$4y = 2x -25x^2$

$\mathrm{ucos} \theta=1$

$usin$ $\theta=2$

$\Rightarrow \tan \theta=2, \mathrm{u}=\sqrt{5}$

equation of trajectory $y=x \tan \theta-\frac{1}{2} g\left(\frac{x}{u \cos \theta}\right)^{2}$

$y=x \times 2-\frac{1}{2} \times 10 \times\left(\frac{x}{1}\right)^{2}$

$y=2 x-5 x^{2}$

Standard 11

Physics

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