A projectile moving vertically upwards with a velocity of $200\, ms^{-1}$ breaks into two equal parts at a height of $490\, m$. One part starts moving vertically upwards with a velocity of $400\, ms^{-1}$. How much time it will take, after the break up with the other part to hit the ground? .............. $\mathrm{s}$
A projectile moving vertically upwards with a velocity of $200\, ms^{-1}$ breaks into two equal parts at a height of $490\, m$. One part starts moving vertically upwards with a velocity of $400\, ms^{-1}$. How much time it will take, after the break up with the other part to hit the ground? .............. $\mathrm{s}$
- [AIEEE 2012]
- A
$2\sqrt {10}$
- B
$5$
- C
$10$
- D
$\sqrt {10}$
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