A projectile thrown with a speed v at an angle θ has a range R on surface of earth. For same v and

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3-2.Motion in Plane

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A projectile thrown with a speed $v$ at an angle $\theta $ has a range $R$ on the surface of earth. For same $v$ and $\theta $, its range on the surface of moon will be

A

$R/6$

B

$6R$

C

$R/36$

D

$36R$

Solution

(b) Range is given by $R = \frac{{{u^2}\sin 2\theta }}{g}$

On moon ${g_m} = \frac{g}{6}$. Hence ${R_m} = 6R$

Standard 11

Physics

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