A proton (mass $ = 1.67 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C)$ enters perpendicular to a magnetic field of intensity $2$ $weber/{m^2}$ with a velocity $3.4 \times {10^7}\,m/\sec $. The acceleration of the proton should be
$6.5 \times {10^{15}}\,m/{\sec ^2}$
$6.5 \times {10^{13}}\,m/{\sec ^2}$
$6.5 \times {10^{11}}\,m/{\sec ^2}$
$6.5 \times {10^9}\,m/{\sec ^2}$
A proton, a deuteron and an $\alpha-$particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is
The direction of magnetic force on the electron as shown in the diagram is along
$\alpha $ particle, proton and duetron enters in a uniform (transverse) magnetic field $'B'$ with same acceleration potential find ratio of radius of path followed by these particles.
A magnetic field
A charged particle moves in a magnetic field $\vec B = 10\,\hat i$ with initial velocity $\vec u = 5\hat i + 4\hat j$ The path of the particle will be