7. MOTION
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एक रेसिंग कार का एकसमान त्वरण $4\, m s ^{-2}$ है। गाति प्रारंभ करने के $10\, s$ पश्चात् वह कितनी दूरी तय करेगी ?

A

$100$

B

$50$

C

$200$

D

$400$

Solution

Initial Velocity of the car, $u =0 \,ms ^{-1}$

Acceleration, $a =4 \,m s ^{-2}$

Time, $t =10 \,s$

We know Distance, $s=u t+(1 / 2)$ at$^{2}$

Therefore, Distance covered by car in $10\, sec$ $=0 \times 10+(1 / 2) \times 4 \times 102$ 

$=0+(1 / 2) \times 4 \times 10 \times 10 \,m$

$=(1 / 2) \times 400 \,m$

$=200 \,m$

Standard 9
Science

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