A racing car has an acceleration of $4\, m s ^{-2} .$ What distance will it cover in $20$ seconds after start ?

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Given $u=0 m s ^{-1}, a=4 m s ^{-2}, t=20 s , S =?$

Using the equation

$S=u t+\frac{1}{2} a t^{2},$ we have

$S=0+\frac{1}{2} \times 4 \times(20)^{2}=800 m$

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