A resistance of 20 ohms is connected to a sou | vedclass

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Question

(d)Peak value to r.m.s. value means, current becomes $\frac{1}{{\sqrt 2 }}$ times.
So from $i = {i_0}\sin 100\pi t \Rightarrow \frac{1}{{\sqrt 2 }} \

Vedclass · Accepted Answer

$2.5 	imes {10^{ - 3}}$ $ sec $

Vedclass · Answer

(d)Peak value to r.m.s. value means, current becomes $\frac{1}{{\sqrt 2 }}$ times.
So from $i = {i_0}\sin 100\pi t \Rightarrow \frac{1}{{\sqrt 2 }} 	imes {i_0} = {i_0}\sin 100\pi t$
$ \Rightarrow \sin \frac{\pi }{4} = \sin 100\pi t \Rightarrow t = \frac{1}{{400}}sec$$ = 2.5 	imes {10^{ - 3}}sec.$

A resistance of $20$ ohms is connected to a source of an alternating potential $V = 220\,sin\,(100\,\pi t)$. The time taken by the current to change from its peak value to r.m.s value is

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