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Question

$\omega=\alpha-\beta t \quad \alpha=\beta t$

$\int \frac{\mathrm{d} 	heta}{\mathrm{dt}}=\int \alpha-\beta \mathrm{t} \quad \mathrm{t}=\alpha / \be

Vedclass · Accepted Answer

$\frac {\alpha ^2}{2\beta }$

Vedclass · Answer

$\omega=\alpha-\beta t \quad \alpha=\beta t$

$\int \frac{\mathrm{d} 	heta}{\mathrm{dt}}=\int \alpha-\beta \mathrm{t} \quad \mathrm{t}=\alpha / \beta$

$\int \mathrm{d} 	heta=\alpha \mathrm{t}-\frac{\beta \mathrm{t}^{2}}{2}$

$	heta=\alpha 	imes \frac{\alpha}{\beta}-\frac{\beta \alpha^{2}}{2 \beta^{2}}=\frac{\alpha^{2}}{2 \beta}$

A rigid body rotates about a fixed axis with variable angular velocity equal to $(\alpha \,-\,\beta t)$ at time $t,$ where $\alpha $ and $\beta $ are constants. The angle through which it rotates before it comes to rest is

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