Gujarati
Hindi
8.Mechanical Properties of Solids
normal

A rigid massless rod of length $6\ L$ is suspended horizontally by means of two elasticrods $PQ$ and $RS$ as given figure. Their area of cross section, young's modulus and lengths are mentioned in figure. Find deflection of end $S$ in equilibrium state. Free end of rigid rod is pushed down by a constant force . $A$ is area of cross section, $Y$ is young's modulus of elasticity

A

$\frac {6FL}{4AY}$

B

$\frac {9FL}{8AY}$

C

$\frac {FL}{6AY}$

D

$\frac {FL}{4AY}$

Solution

In equilibrium condition

$S_{Q}=\frac{T_{s}\left(\frac{3 L}{2}\right)}{2 A(2 Y)}=\frac{9 F L}{8 A Y}$

$\mathrm{F}=\mathrm{T}_{\mathrm{S}}-\mathrm{T}_{\mathrm{Q}}$

$\mathrm{F}(6 \mathrm{L})=\mathrm{T}_{\mathrm{D}}(2 \mathrm{L})$

$\mathrm{T}_{\mathrm{S}}=3 \mathrm{F}$

$\mathrm{T}_{Q}=2 \mathrm{F}$

Standard 11
Physics

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