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7.Gravitation
medium
A satellite moves in a circle around the earth. The radius of this circle is equal to one half of the radius of the moon’s orbit. The satellite completes one revolution in
A
$\frac{1}{2}$ lunar month
B
$\frac{2}{3}$ lunar month
C
${2^{ - 3/2}}$ lunar month
D
${2^{3/2}}$ lunar month
Solution
(c) Time period of revolution of moon around the earth = $1$ lunar month.
$\frac{{{T_s}}}{{{T_m}}} = {\left( {\frac{{{r_s}}}{{{r_m}}}} \right)^{3/2}} = {\left( {\frac{1}{2}} \right)^{3/2}}$
${T_s} = {2^{ – 3/2}}$ lunar month.
Standard 11
Physics
