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7.Gravitation
medium
The satellite of mass $m$ revolving in a circular orbit of radius $r$ around the earth has kinetic energy $E$. Then its angular momentum will be
A
$\sqrt {\frac{E}{{m{r^2}}}} $
B
${\frac{E}{{2m{r^2}}}}$
C
$\sqrt {2Em{r^2}} $
D
$\sqrt {2Emr} $
Solution
Angular momentum
$L=m v r$
$V=\sqrt{\frac{2 E}{m}}$
$\mathrm{L}=\mathrm{m} \sqrt{\frac{2 \mathrm{E}}{\mathrm{m}}} \mathrm{r} \Rightarrow \sqrt{2 \mathrm{Emr}^{2}}$
Standard 11
Physics