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7.Gravitation
easy
A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is $2$ times that of the earlier orbit. The time period in the second orbit is
A
$4.8$ hours
B
$48\sqrt 2 $ hours
C
$24$ hours
D
$24\sqrt 2 $ hours
Solution
(b) $T \propto {r^{3/2}}$. If $r$ becomes double then time period will becomes $(2)^{3/2}$ times.
So new time period will be $24 \times 2\sqrt 2 \;hr$ i.e. $T = 48\sqrt 2 $
Standard 11
Physics