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6-2.Equilibrium-II (Ionic Equilibrium)
hard
A saturated solution of $A{g_2}S{O_4}$ is $2.5 \times {10^{ - 2}}$ $M$; The value of its solubility product is
A
$62.5 \times {10^{ - 6}}$
B
$6.25 \times {10^{ - 4}}$
C
$15.625 \times {10^{ - 6}}$
D
$3.125 \times {10^{ - 6}}$
Solution
(a) For $A{g_2}S{O_4} \to \mathop {2A{g^ + }}\limits_{2x} + \mathop {SO_4^{ 2 – }}\limits_x $
${K_{sp}} = {(2x)^2}.x$ ; ${K_{sp}} = 4{x^3}$ ; ${K_{sp}} = 4 \times {(2.5 \times {10^{ – 2}})^3}$
${K_{sp}} = 62.5 \times {10^{ – 6}}$
Standard 11
Chemistry
