A shopkeeper buys 144 items at 90 paisa each. On way 20 items are broken. He sells remainder at

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7.Profit and Loss

hard

A shopkeeper buys $144$ items at $90$ paisa each. On the way $20$ items are broken. He sells the remainder at $RS.\,1.20$ each. His gain percent correct to one place of decimal is

A

$13.8$

B

$14.6$

C

$14.8$

D

$15.8$

Solution

$20$ items are broken out of $144$ items.

$\therefore$ $C.P.$ of $124$ items.

$=₹\left(\frac{144 \times 90}{100}\right)=₹ 129.60$

Total $S.P.$ $=₹(1.20 \times 124)=Rs. 148.8$

$\therefore \quad$ Gain $=₹(148.80-129.60)=₹ 19.20$

$\therefore \quad$ Gain percent $=\frac{19.20}{129.60} \times 100=14.8 \%$

Standard 13

Quantitative Aptitude

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