A simple pendulum executing S.H.M. is falling | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $ T = 2\pi \sqrt{\frac{l}{g}}$; for freely falling system effective $g = 0$
so $T = \infty $ or $n = 0$
It means that pendulum does not oscillat

Vedclass · Accepted Answer

It does not oscillate at all

Vedclass · Answer

(c) $ T = 2\pi \sqrt{\frac{l}{g}}$; for freely falling system effective $g = 0$
so $T = \infty $ or $n = 0$
It means that pendulum does not oscillate at all.

A simple pendulum executing $S.H.M.$ is falling freely along with the support. Then

Similar Questions

A man having a wrist watch and a pendulum clock rises on a $TV$ tower. The wrist watch and pendulum clock per chance fall from the top of the tower. Then

The angular amplitude of a simple pendulum is $\theta_0$. The maximum tension in its string will be

For a simple pendulum the graph between $L$ and $T$ will be.

The ratio of frequencies of two pendulums are $2 : 3$, then their length are in ratio

Can simple pendulum clock be used in an artificial satellite ? Why ?