A smooth rightangled wedge of mass $M$ is kept on a smooth horizontal surface as shown. A mass $m$ is released from top of wedge when $m$ reaches ground its speed is $V$. Work done by normal contact force on $m$, while it comes down to ground is :-

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  • A

    $\frac{-1}{2}\ mv^2$

  • B

    $\frac{-1}{2}\ Mv^2$

  • C

    $\frac{-1}{2} \frac{m^2v^2}{M}$

  • D

    $\frac{-1}{2} \frac{M^2v^2}{m}$

Similar Questions

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A$ : Body $'P'$ having mass $M$ moving with speed $'u'$ has head-on collision elastically with another body $'Q'$ having mass $'m'$ initially at rest. If $m< < M,$ body $'Q'$ will have a maximum speed equal to $'2u'$ after collision.

Reason $R$ : During elastic collision, the momentum and kinetic energy are both conserved.

In the light of the above statements, choose the most appropriate answer from the options given below:

  • [JEE MAIN 2021]

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