A smooth rightangled wedge of mass $M$ is kept on a smooth horizontal surface as shown. A mass $m$ is released from top of wedge when $m$ reaches ground its speed is $V$. Work done by normal contact force on $m$, while it comes down to ground is :-
$\frac{-1}{2}\ mv^2$
$\frac{-1}{2}\ Mv^2$
$\frac{-1}{2} \frac{m^2v^2}{M}$
$\frac{-1}{2} \frac{M^2v^2}{m}$
Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$ : Body $'P'$ having mass $M$ moving with speed $'u'$ has head-on collision elastically with another body $'Q'$ having mass $'m'$ initially at rest. If $m< < M,$ body $'Q'$ will have a maximum speed equal to $'2u'$ after collision.
Reason $R$ : During elastic collision, the momentum and kinetic energy are both conserved.
In the light of the above statements, choose the most appropriate answer from the options given below:
A ball impinges directly on a similar ball at rest. If $1/4^{th}$ of the kinetic energy is lost by the impact, the value of coefficient of restitution is
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Two cars, both of mass $m$ , collide and stick together. Prior to the collision, one car had been traveling north at speed $2v$ , while the second was traveling at speed $v$ at an angle $\phi $ south of east (as indicated in the figure). The magnitude of the velocity of the two car system immediately after the collision is
Six identical balls are lined in a straight groove made on a horizontal frictionless surface as shown. Two similar balls each moving with a velocity $v$ collide elastically with the row of $6$ balls from left. What will happen