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Question

$(K . E .)_{T}+(K . E .)_{R} \geq P . E$

$\frac{1}{2} m v^{2}+\frac{1}{2} I \omega^{2} \geq m g h$

$\frac{1}{2} m v^{2}+\frac{1}{2}\left(\frac{2

Vedclass · Accepted Answer

$ \ge \sqrt {\frac{{10}}{7}gh} $

Vedclass · Answer

$(K . E .)_{T}+(K . E .)_{R} \geq P . E$

$\frac{1}{2} m v^{2}+\frac{1}{2} I \omega^{2} \geq m g h$

$\frac{1}{2} m v^{2}+\frac{1}{2}\left(\frac{2}{5} m r^{2}\right) \omega^{2} \geq m g h$

$\frac{7}{10} m v^{2} \geq m g h$

$v \geq \sqrt{\frac{10 g h}{7}}$

A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity $v\,\,m/s.$ If it is to climb the inclined surface then $v$ should be

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