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1.Solution and Colligative properties
hard
A solution of two miscible liquids showing negative deviation from Raoult's law will have :
A
increased vapour pressure, increased boiling point
B
increased vapour pressure, decreased boiling point
C
decreased vapour pressure, decreased boiling point
D
decreased vapour pressure, increased boiling point
(JEE MAIN-2024)
Solution
Solution with negative deviation has
$ \mathrm{P}_{\mathrm{T}}<\mathrm{P}_{\mathrm{A}^0} \mathrm{X}_{\mathrm{A}} +\mathrm{P}_{\mathrm{B}^0} \mathrm{X}_{\mathrm{B}} $
$ \mathrm{P}_{\mathrm{A}}<\mathrm{P}_{\mathrm{A}^0} \mathrm{X}_{\mathrm{A}} $
$ \mathrm{P}_{\mathrm{B}}<\mathrm{P}_{\mathrm{B}^0} \mathrm{X}_{\mathrm{B}} $
If vapour pressure decreases so boiling point increases.
Standard 12
Chemistry
