A sphere strikes a wall and rebounds with coe | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$e=\frac{V}{u}$

$\left(v \cos 60^{\circ}\right)=e u_{x}$

$\frac{v}{2}=\frac{1}{3} u_{x}$

$U_{x}=\frac{3}{2} V$

$v \sin 60^{\circ}=u _g$

Vedclass · Accepted Answer

$66 \frac{2}{3}\%$

Vedclass · Answer

$e=\frac{V}{u}$

$\left(v \cos 60^{\circ}ight)=e u_{x}$

$\frac{v}{2}=\frac{1}{3} u_{x}$

$U_{x}=\frac{3}{2} V$

$v \sin 60^{\circ}=u _g$

$u_g=\frac{\sqrt{v\sqrt {3}}}{2}$

$u=\sqrt{u_{2}^{2}+u_{g}^{2}}=$ $\sqrt{v^{2} \frac{3}{4}+\frac{9}{4} v^{2}}$

$u=v \sqrt{\frac{12}{4}}=\frac{v}{2} \sqrt{12}=v \sqrt{3} m/a$

$u=0.1 	imes \sqrt{3} \,\,\,\mathrm{m/a}$

$V=0.1 \mathrm{m/a}$

$k \cdot E_{i}=\frac{1}{2} m u^{2}=\frac{1}{2} m(0-1)^{2}	imes3$

$k \cdot {E}_{f}=\frac{1}{2} m v^{2}=\frac{1}{2} m(0.1)^{2}$

$\Delta K \cdot {E}=k \cdot E_{i}-k \cdot E_{f}$

$=\frac{1}{2} m(0.1)^{2}(3-1)$

$=\frac{1}{2} m(0-1)^{2} 	imes 2$

$K \cdot E_2=\frac{\Delta K \cdot E}{k \cdot E_{i}}=\frac{\frac{1}{2} m(0.1)^{2} 	imes 2}{\frac{1}{2} m\left(0.1)^{2} 	imes 3ight.} 	imes 100$

$k.E=\frac{200}{3}$$=66 \frac{2}{3}\%$

A sphere strikes a wall and rebounds with coefficient of restitution $1/3$. If it rebounds with a velocity of $0.1\, m/sec$ at an angle of $60^o$ to the normal to the wall, the loss of kinetic energy is

Similar Questions

Define elastic collision. Define inelastic collision.

A ball loses $15.0\%$ of its kinetic energy when it bounces back from a concrete wall. With what speed you must throw it vertically down from a height of $12.4\, m$ to have it bounce back to the same height (ignore air resistance)? ............. $\mathrm{m} / \mathrm{s}$

In an elastic collision between disks $A$ and $B$ of equal mass but unequal radii, $A$ moves along the $x$ -axis and $B$ is stationary before impact. Which of the following is possible after impact?

A billiard ball moving with a speed of $5 \,m/s$ collides with an identical ball originally at rest. If the first ball stops after collision, then the second ball will move forward with a speed of ........... $m{s^{ - 1}}$