A spherical soap bubble has in ternal pressure $P_0$ and radius $r_0$ and is in equilibrium in an enclosure with pressure ${P_1} = \frac{{8{P_0}}}{9}$ . The enclosure is gradually evacuated . Assuming temperature and surface tension of soap bubble to be fixed find the value of $\frac{{{\rm{final\,\, radius}}}}{{{\rm{initial\,\, radius}}}}$ of soap bubble
$0$
$1$
$3$
$7$
Air (density $\rho$ ) is being blown on a soap film (surface tension $T$ ) by a pipe of radius $R$ with its opening right next to the film. The film is deformed and a bubble detaches from the film when the shape of the deformed surface is a hemisphere. Given that the dynamic pressure on the film due to the air blown at speed $v$ is $\frac{1}{2} \rho v^{2}$, the speed at which the bubble formed is
There are two liquid drops of different radii. The excess pressure inside over the outside is
A $U-$ tube with limbs of diameters $5\, mm$ and $2\, mm$ contains water of surface tension $7 \times 10^{-2}$ newton per metre, angle of contact is zero and density $10^3\, kg/m^3$. If $g$ is $10 \,m/s^2$, then the difference in level of two limbs is :-
There is an air bubble of radius $1.0\,mm$ in a liquid of surface tension $0.075\,Nm ^{-1}$ and density $1000\,kg$ $m ^{-3}$ at a depth of $10\,cm$ below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is $....Pa \left( g =10\,ms ^{-2}\right)$
A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.
$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$