A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.

$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$

If the surface tension of a soap solution is $0.03\, MKS$ units, then the excess of pressure inside a soap bubble of diameter $6 \,mm$ over the atmospheric pressure will be

If pressure at half the depth of a lake is equal to $2/3$ pressure at the bottom of the lake then what is the depth of the lake...... $m$

A soap bubble has radius $R$ and thickness $d ( < < R)$ as shown. It colapses into a spherical drop. The ratio of excess pressure in the drop to the excess pressure inside the bubble is 

When two soap bubbles of radii $a$ and $b ( b > a )$ coalesce, the radius of curvature of common surface is

Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is