A spring 40,mm long is stretched by application of a force. If 10, N force is required to stretch sp

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5.Work, Energy, Power and Collision

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A spring $40\,mm$ long is stretched by the application of a force. If $10\, N$ force is required to stretch the spring through $1\, mm$, then work done in stretching the spring through $40\, mm$ is ............. $\mathrm{J}$

A

$84$

B

$68$

C

$23$

D

$8$

Solution

Here $\mathrm{k}=\frac{\mathrm{F}}{\mathrm{x}}=\frac{10}{1 \times 10^{-3}}=10^{4} \mathrm{N} / \mathrm{m}$

$\mathrm{W}=\frac{1}{2} \mathrm{kx}^{2}=\frac{1}{2} \times 10^{4} \times\left(40 \times 10^{-3}\right)^{2}=8 \mathrm{J}$

Standard 11

Physics

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