A spring is compressed between two toy carts of masses $m_1$ and $m_2$. When the toy carts are released the spring exerts equal and opposite forces for the same time $t$ on each toy cart. If the coefficients of friction $\mu $ between the ground and the toy carts are equal, then the displacement of the toy carts are in the ratio
$\frac{{{s_1}}}{{{s_2}}} = \frac{{{m_2}}}{{{m_1}}}$
$\frac{{{s_1}}}{{{s_2}}} = \frac{{{m_1}}}{{{m_2}}}$
$\frac{{{s_1}}}{{{s_2}}} = {\left( {\frac{{{m_2}}}{{{m_1}}}} \right)^2}$
$\frac{{{s_1}}}{{{s_2}}} = {\left( {\frac{{{m_1}}}{{{m_2}}}} \right)^2}$
Two masses of $1 \,gm$ and $4 \,gm$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is
If a man increase his speed by $2 \,m/s$ , his K.E. is doubled, the original speed of the man is
Masses of two substances are $1\, g$ and $9\, g$ respectively. If their kinetic energies are same, then the ratio of their momentum will be
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If the momentum of a body is increased by $100\%$, then the percentage increase in the kinetic energy is ............ $\%$