A spring of force constant 800, N/m has an extension of 5,cm . work done in extending it from 5,cm t

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5.Work, Energy, Power and Collision

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A spring of force constant $800\, N/m$ has an extension of $5\,cm$. The work done in extending it from $ 5\,cm$ to $15 \,cm$ is ............. $\mathrm{J}$

A

$16$

B

$8$

C

$32$

D

$24$

(AIEEE-2002)

Solution

(b)$W = \frac{1}{2}k(x_2^2 – x_1^2) = \frac{1}{2} \times 800 \times ({15^2} – {5^2}) \times {10^{ – 4}}$$ = 8\,J$

Standard 11

Physics

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