Gujarati
Hindi
12.Kinetic Theory of Gases
normal

A thermally insulated vessel contains an ideal gas of molecular mass $M$ and ratio of specific heats $\gamma $. It is moving with speed $v$ and its suddenly brought to rest. Assuming no heat is lost to the surroundings, its temperature` increases by

A

$\frac{{(\gamma  - 1)}}{{2\gamma R}}M{v^2}K$

B

$\frac{{\gamma M{v^2}}}{{2R}}K$

C

$\frac{{(\gamma  - 1)}}{{2R}}M{v^2}K$

D

$\frac{{(\gamma  - 1)}}{{2(\gamma  + 1)R}}M{v^2}K$

Solution

As no heat is lost,

Loss of kinetic energy $=$ gain of internal energy of gas

$ \frac{1}{2} m v^{2}=n C_{V} \Delta T$

$\Rightarrow \quad  \frac{1}{2} m v^{2}=\frac{m}{M} \cdot \frac{R}{\gamma-1} \Delta T$

$\Rightarrow \quad  \Delta T=\frac{m v^{2}(\gamma-1)}{2 R} K$

Standard 11
Physics

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