A thin rod of length $L$ is bent to form a semicircle. The mass of rod is $M$. What will be  the gravitational potential at the centre of the circle?

  • A

    $-\frac{GM}{L}$

  • B

    $-\frac{GM}{2 \pi L}$

  • C

    $-\frac{\pi GM}{2L}$

  • D

    $-\frac{\pi GM}{L}$

Similar Questions

If gravitational potential in a region is given by $v = 4x^2$. Then gravitational field is

If $V$ is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:-

  • [JEE MAIN 2023]

If potential at the surface of earth is assigned zero value, then potential at centre of earth will be (Mass $=M$, Radius $=R$ )

A particle of mass $M$ is at a distance a from surface of a thin spherical shell of equal mass and having radius a.

Two concentric shells have masses $M$ and $m$ and their raddi are $R$ and $r$ respectively where $R > r$, if $x$ be the distance from the common centre, then what is the gravitational potential at a point for which $r < x < R$