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6.Permutation and Combination
easy
A total number of words which can be formed out of the letters $a,\;b,\;c,\;d,\;e,\;f$ taken $3$ together such that each word contains at least one vowel, is
A
$72$
B
$48$
C
$96$
D
None of these
Solution
(c) The required number of words is
${(^2}{C_1}{ \times ^4}{C_2}{ + ^2}{C_2}{ \times ^4}{C_1})3\;!\; = 96$.
Standard 11
Mathematics