A train is running at 20 ,m / s on a railway line with radius of curvature 40,000 metres. distance b

English

Gujarati

Hindi

4-1.Newton's Laws of Motion

medium

A train is running at $20 \,m / s$ on a railway line with radius of curvature $40,000$ metres. The distance between the two rails is $1.5$ metres. For safe running of train the elevation of outer rail over the inner rail is ......$mm$ $\left( g =10 \,m / s ^2\right)$

A$2.0$

B$1.75$

C$1.50$

D$1.25$

Solution

(c)
$\tan \theta=\frac{h}{d}=\frac{v^2}{r g}$
$h=\frac{(1.5)(20)(20)}{40,000 \times 10}$
$=1.5 \,mm$

Standard 11

Physics

Share

Similar Questions

A horizontal curve on $a$ racing track is banked at a $45^o $ angle. When a vehicle goes around this curve at the curve’s safe speed (no friction needed to stay on the track), what is its centripetal acceleration?

medium

A train runs along an unbanked circular track of radius $30 \;m$ at a speed of $54\; km / h$ The mass of the train is $10^{6}\; kg$. What provides the centripetal force required for this purpose – The engine or the rails? What is the angle of banking required to prevent wearing out of the rail?

easy

An aircraft executes a horizontal loop at a speed of $720\; km/h$ with its wings banked at $15^o$. What is the radius of the loop in $km$?

medium

A car moving on a horizontal road may be thrown out of the road in taking a turn

easy

A smooth circular groove has a smooth vertical wall as shown in figure. A block of mass $m$ moves against the wall with a speed $v$. Which of the following curve represents the correct relation between the normal reaction on the block by the wall $( N )$ and speed of the block $(v)$ ?

medium

(JEE MAIN-2022)