A uniform metal wire of density ρ , cross-sectional area A and length L is stretched with a tension

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14.Waves and Sound

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A uniform metal wire of density $\rho $, cross-sectional area $A$ and length $L$ is stretched with a tension $T$. The speed of transverse wave in the wire is given by

A

$\sqrt {\frac{{TL}}{{\rho A}}} $

B

$\sqrt {\frac{{T\rho }}{{AL}}} $

C

$\sqrt {\frac{T}{{A\rho }}} $

D

$\sqrt {\frac{{T\rho }}{A}} $

Solution

$\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mathrm{m}}}=\sqrt{\frac{\mathrm{TL}}{\mathrm{M}}} \quad[\because \mathrm{m}=$ mass per unit

$v=\sqrt{\frac{T L}{(A L) p}}=\sqrt{\frac{T}{A p}} \quad$ length $=\frac{M}{L} ]$

Standard 11

Physics

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