A uniform solid cylinder of mass M and radius | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Tension in the both string will be same.

$m g-T=m a....(1)$

also Inertia solid cylinder is $M R^{2} / 2$ Torque at centre of cylinder due to bot

Vedclass · Accepted Answer

$\frac{{4mg}}{{M + 4m}}$

Vedclass · Answer

Tension in the both string will be same.

$m g-T=m a....(1)$

also Inertia solid cylinder is $M R^{2} / 2$ Torque at centre of cylinder due to both string $2 T 	imes R=I \alpha=M R^{2} \alpha / 2 \ldots(2)$

also, $a=\alpha R....(3)$

From equations $(1),(2)$ and $(3)$

we get Tension $T=\frac{M m g}{M+4 m}$

A uniform solid cylinder of mass $M$ and radius $R$ rotates about a frictionless horizontal axle. Two similar masses suspended with the help two ropes wrapped around the cylinder. If the system is released from rest then the acceleration of each mass will be

Similar Questions

"In pure translation motion velocity of every particle of body at any instant" is what? Equal or unequal ?

Let $\mathop A\limits^ \to $ be a unit vector along the axis of rotation of a purely rotating body and $\mathop B\limits^ \to $ be a unit vector along the velocity of a particle $ P$ of the body away from the axis. The value of $\mathop A\limits^ \to .\mathop B\limits^ \to $ is

Two blocks which are connected to each other by means of a massless string are placed on two inclined planes as shown in figure. After releasing from rest, the magnitude of acceleration of the centre of mass of both the blocks is $(g = 10\, m/s^2)$

A cylinder of mass $M$ and radius $r$ is mounted on a frictionless axle over a well. A rope of negligible mass is wrapped around the cylinder and a bucket of mass $m$ is suspended from the rope. The linear acceleration of the bucket will be

Difference between rigid body and solid body.